Clonezilla 3 0 0 32 bit

When you need to create an image of your computer, you usually have to store the image somewhere. Where did you leave that boot cd with your favorite image software and where to store the image? Store on NAS device, external USB device or DVD? You can use one device for both! This article describes how you can configure a USB device with 2 partitions where the first partition will contain the image software and the 2nd partition will be used for storing the images. That way you only need 1 (USB) device for creating and storing image(s) of your computer(s). I’ll be using the free Clonezilla imaging software. Setup is done from a (live) Linux environment. The first partition on the USB device can be recognized by Windows (FAT), the 2nd partition only by Linux and Clonezilla (EXT2/3). From (live) linux environment, create an empty USB device When running VMware, you may have to connect your USB device through Virtual Machine, Removable Devices, , Connect. Determine your device ID using the ‘dmesg’ command, its output will look like this: [62249.491845] sdb: [62249.532482] sd 3:0:0:0: [sdb] No Caching mode page present [62249.532490] sd 3:0:0:0: [sdb] Assuming drive cache: write through [62249.532575] sd 3:0:0:0: [[b]sdb[/b]] Attached SCSI removable disk Open in new window Device ID is sdb in this case. When your USB device contains data your Linux environment may mount the device automatically, in that case, using the ‘mount’ command, find out where it is mounted: /dev/sdb on /media/42D3-B580 type vfat (rw,nosuid,nodev,uid=1000,gid=1000,shortname=mixed,dmask=0077,utf8=1,showexec,flush,uhelper=udisks) Open in new window It is mounted on /media/42D3-B580 in this case. Unmount it using the ‘umount’ command, like this: umount /media/42D3-B580 Open in new window Checking with ‘mount’ will show you that the USB device is not mounted anymore. As ‘root’ delete any existing partitions using the fdisk /dev/, d command, like this: fdisk /dev/sdb Command (m for help): d Partition number (1-4): 2 Open in new window Repeat until all partitions are deleted: Command (m for help): d Selected partition 4 Command (m for help): p Disk /dev/sdb: 16.0 GB, 16039018496 bytes 64 heads, 32 sectors/track, 15296 cylinders, total 31326208 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Device Boot Start End Blocks Id System Command (m for help): Open in new window Write changes to your

Tải xuống FileZilla cho Linux 3.55.0 (64-bit)Nhấn vào đây nếu trang web tải về chưa khởi chạy. Liên kết tải xuống FileZilla cho Linux 3.55.0 (64-bit) được mở ở trang web bên ngoài.Xem thêm các liên kết tải xuống khác dưới đây.Báo không tải đượcFileZilla for Linux 3.55.0 là phần mềm quản lý nguồn dữ liệu FTP trên nền tảng Linux. Nó thực sự hữu ích cho cả việc upload và download dữ liệu trao đổi qua FTP. Clonezilla LiveCD (64-bit) for Linux Clonezilla là công cụ sao lưu ổ cứng tương tự như Norton Ghost, nhưng là mã nguồn mở, miễn phí và tốt. Xếp hạng: 3 1 Phiếu bầuSử dụng: Miễn phí 669 Tải về FileZilla cho Linux Phần mềm tải dữ liệu lên server nhanh chóng FileZilla for Linux 3.55.0 là phần mềm quản lý nguồn dữ liệu FTP trên nền tảng Linux. Nó thực sự hữu ích cho cả việc upload và download dữ liệu trao đổi qua FTP. Xếp hạng: 3 1 Phiếu bầuSử dụng: Miễn phí 845 Tải về Pogoplug for Linux Với Pogoplug, bạn không cần phải đem theo lỉnh kỉnh các ổ cứng USB trong người, chỉ cần để chúng tại nhà hoặc văn phòng, cắm tất cả vào máy Pogoplug Xếp hạng: 3 1 Phiếu bầuSử dụng: Dùng thử 199 Tải về Clonezilla LiveCD (32-bit) for Linux Clonezilla là công cụ sao lưu ổ cứng tương tự như Norton Ghost, nhưng là mã nguồn mở, miễn phí và tốt. Xếp hạng: 3 1 Phiếu bầuSử dụng: Miễn phí 618 Tải về Flick for Linux Phần mềm chuyển dữ liệu không dây cho Linux Flick for Linux cung cấp cho người dùng Linux một công cụ chia sẻ dữ liệu tiện ích, thông minh, đa nền tảng và hoàn toàn miễn phí. Xếp hạng: 3 1 Phiếu bầuSử dụng: Miễn phí 103 Tải về ; Xem thêm Dữ liệu - File

Rate mode : Constant Bit rate : 640 kb/s Channel(s) : 6 channels Channel layout : L R C LFE Ls Rs Sampling rate : 48.0 kHz Frame rate : 31.250 FPS (1536 SPF) Bit depth : 32 bits Compression mode : Lossy Stream size : 250 MiB (40%) Title : angličtina [Originál] Language : English Service kind : Complete Main Default : Yes Forced : No VENDOR_ID : [0][0][0][0] Audio #2 ID : 3 Format : E-AC-3 Format/Info : Enhanced AC-3 Commercial name : Dolby Digital Plus Codec ID : A_EAC3 Duration : 54 min 39 s Bit rate mode : Constant Bit rate : 128 kb/s Channel(s) : 2 channels Channel layout : L R Sampling rate : 48.0 kHz Frame rate : 31.250 FPS (1536 SPF) Bit depth : 32 bits Compression mode : Lossy Stream size : 50.0 MiB (8%) Title : angličtina [Originál] Language : English Service kind : Complete Main Default : Yes Forced : No VENDOR_ID : [0][0][0][0] Audio #3 ID : 4 Format : E-AC-3 Format/Info : Enhanced AC-3 Commercial name : Dolby Digital Plus Codec ID : A_EAC3 Duration : 54 min 39 s Bit rate mode : Constant Bit rate : 128 kb/s Channel(s) : 2 channels Channel layout : L R Sampling rate : 48.0 kHz Frame rate : 31.250 FPS (1536 SPF) Bit depth : 32 bits Compression mode : Lossy Stream size : 50.0 MiB (8%) Title : španělština Language : Spanish Service kind : Complete Main Default : Yes Forced : No VENDOR_ID : [0][0][0][0]

Partition table. Syncing disks. vmmint01 etc # Open in new window -> You now have 2 partitions on your USB device (without file systems). Create file systems:vmmint01 etc # mkfs.vfat /dev/sdb1 mkfs.vfat 3.0.9 (31 Jan 2010) vmmint01 etc # vmmint01 etc # mkfs.ext3 /dev/sdb2 mke2fs 1.41.14 (22-Dec-2010) Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=0 blocks, Stripe width=0 blocks 934720 inodes, 3736320 blocks 186816 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=3829399552 115 block groups 32768 blocks per group, 32768 fragments per group 8128 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208 Writing inode tables: done Creating journal (32768 blocks): done Writing superblocks and filesystem accounting information: done This filesystem will be automatically checked every 31 mounts or 180 days, whichever comes first. Use tune2fs -c or -i to override. vmmint01 etc # Open in new window Creating the 2nd partition can take some time, please be patient. Note: Windows will only recognize 1 partition on a USB device so it will only see the first 700Mb. -> You now have 2 partitions on your USB device with file systems. Unplug and plug in your USB device and most Linux systems will automount your 2 devices. Install live recovery tooling like Clonezilla on 1st partition, bootable This is how you can install Clonezilla onto the 1st partition of your USB device. I use unetbootin, both available for Linux and Windows. See: and: Get Clonezilla live .iso from here: Get/install unetbootin (see here), then start unetbootin and select ‘DiskImage’ where you browse ‘...’ to the Clonezilla .iso image file, at ‘Type’ select ‘USB Drive’ and the important choice is at ‘Drive’ where you select /dev/sdb1 and press ‘OK’. Note: unetbootin will only ‘see’ the /dev/sdb1 and /dev/sdb2 devices when they are mounted. unetbootin may give an ‘overwrite’ warning -> acknowledge that. When finished, press ‘OK’, or ‘Reboot’ if you want to reboot now. You have to set the BIOS of your computer to boot from USB. When unetbootin has finished, you are ready to make your first image/backup, just reboot with your USB device. -> You now have a bootable USB device with Clonezilla live on the first partition and available data storage on the 2nd partition. Clonezilla manual: for reading this article. If you find it useful, you can click 'Good Article'

× 10-1 Concept:32-bit floating-point representation of a binary number in IEEE- 754 is Sign (1 bit) Exponent (8 bit) Mantissa bit (23 bits) Calculation:Given binary number is00111110011011010000000000000000Here, sign bit is 0. So, number is positive. 0 01111100 11011010000000000000000 Exponent bits = E = 01111100 = 124 (in decimal)Mantissa bits M = 11011010000000000000000In IEEE-754 format, 32-bit (single precision) (-1)s × 1.M × 2E – 127 = (-1)0 × 1.1101101 × 2124 – 127= 1.1101101 × 2-3= (1 + 2-1 + 2-2 + 2-4 + 2-5 + 2-7) × 2-3= 0.231 = 2.31 × 10-1 ≈ 2.27 × 10-1 In IEEE floating point representation, the hexadecimal number 0xC0000000 corresponds to –3.0–1.0–4.0–2.0Answer (Detailed Solution Below) Option 4 : –2.0 Concept:32-bit floating-point representation of a binary number in IEEE- 754 is Sign (1 bit) Exponent (8 bit) Mantissa bit (23 bits) Calculation:Binary number is0xC0000000 = (11000000000000000000000000000000)2Here, the sign bit is 1. So, the number is negative. 1 10000000 00000000000000000000000 Exponent bits = E = 10000000 = 128 (in decimal)Mantissa bits M = 00000000000000000000000In IEEE-754 format, 32-bit (single precision)(-1)s × 1.M × 2E – 127= (-1)1 × 1. 0 × 2128 – 127= -1 × 1.0 × 2= -2In IEEE floating-point representation, the hexadecimal number 0xC0000000 corresponds to -2. Let R1 and R2 be two 4-bit registers that store numbers in 2’s complement form. For the operation R1 + R2, which one of the following values of R1 and R2 gives an arithmetic overflow? R1 = 1011 and R2 = 1110R1 = 1100 and R2 = 1010R1 = 0011 and R2 = 0100R1 = 1001 and R2 = 1111Answer (Detailed Solution Below) Option 2 : R1 = 1100 and R2 = 1010 The correct answer is option 2.Concept:Stored numbers in registers R1 and R2 are in 2's complement form. Register size is 4 bits. The range of numbers in 2's complement form is -8 to +7. If R1 + R2, the result is out of the above range, then it is overflow.The given data,Given two four-bit registers R1 and R2.Option 1: R1 = 1011 and R2 = 1110False, R1 = 1 0 1 1 = -(0101)= -5+ R2 = 1 1 1 0 = -(0010)= -2----------------------------------------------- 1 0 0 1 = = -7 Here No overflow occurred, because sign bit is same for (R1 + R2 ).Option 2: R1 = 1100 and R2 = 1010True,R1 = 1 1 0 0 = -(0100)= -4+ R2 = 1 0 1 0 = -(0110)= -6 -------------------------------------------- 0 1 1 0 = = -10 Here Overflow occurred because the sign bit is different for (R1 + R2 ).Option 3: R1 = 0011 and R2 = 0100False,R1 = 0 0 1 1 = +(0011)= +3+ R2 = 0 1 0

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